Magnetic force on a moving charge: F = q v B. A proton (q = 1.6×10^-19 C) moves at v = 1.5×10^6 m/s perpendicular to B = 0.2 T. What is F?

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Multiple Choice

Magnetic force on a moving charge: F = q v B. A proton (q = 1.6×10^-19 C) moves at v = 1.5×10^6 m/s perpendicular to B = 0.2 T. What is F?

Explanation:
The magnetic force on a moving charge is F = q v B when the velocity is perpendicular to the magnetic field, so the angle factor is 1. Plugging in q = 1.6×10^-19 C, v = 1.5×10^6 m/s, and B = 0.2 T gives F = (1.6×10^-19)(1.5×10^6)(0.2) = 4.8×10^-14 N. So the magnitude is about 4.8×10^-14 N. The direction would be perpendicular to both v and B, given by the right-hand rule for a proton. The other numbers would arise from incorrect handling of the exponents or missing the sin(θ) factor, which here is 1 since motion is perpendicular.

The magnetic force on a moving charge is F = q v B when the velocity is perpendicular to the magnetic field, so the angle factor is 1. Plugging in q = 1.6×10^-19 C, v = 1.5×10^6 m/s, and B = 0.2 T gives F = (1.6×10^-19)(1.5×10^6)(0.2) = 4.8×10^-14 N.

So the magnitude is about 4.8×10^-14 N. The direction would be perpendicular to both v and B, given by the right-hand rule for a proton. The other numbers would arise from incorrect handling of the exponents or missing the sin(θ) factor, which here is 1 since motion is perpendicular.

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