In Bohr’s model, the angular momentum L = nħ. What is L for n = 3 in terms of ħ?

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Multiple Choice

In Bohr’s model, the angular momentum L = nħ. What is L for n = 3 in terms of ħ?

Explanation:
In Bohr’s model, the orbital angular momentum is quantized in units of the reduced Planck constant, so L = nħ with n as a positive integer. This means the angular momentum comes in discrete steps: 1ħ, 2ħ, 3ħ, and so on as n increases. For n = 3, the angular momentum is three times ħ, i.e., L = 3ħ (about 3.16 × 10^-34 J·s). The other values correspond to different quantum numbers (for example, n = 2 gives 2ħ, n = 1 gives ħ), but the case asked yields 3ħ.

In Bohr’s model, the orbital angular momentum is quantized in units of the reduced Planck constant, so L = nħ with n as a positive integer. This means the angular momentum comes in discrete steps: 1ħ, 2ħ, 3ħ, and so on as n increases. For n = 3, the angular momentum is three times ħ, i.e., L = 3ħ (about 3.16 × 10^-34 J·s). The other values correspond to different quantum numbers (for example, n = 2 gives 2ħ, n = 1 gives ħ), but the case asked yields 3ħ.

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