In Bohr’s model, the angular momentum of the electron in the n = 1 orbit is L = nħ. What is L for n = 1 in terms of ħ?

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Multiple Choice

In Bohr’s model, the angular momentum of the electron in the n = 1 orbit is L = nħ. What is L for n = 1 in terms of ħ?

Explanation:
In Bohr’s model, the orbital angular momentum is quantized in units of ħ: L = nħ, where n is the principal quantum number for the orbit. For the ground state, n = 1, so the angular momentum has magnitude L = ħ. This means the electron carries one quantum of orbital angular momentum in the lowest orbit. (Spin would add its own ±ħ/2 contribution, but the orbital part in this model is nonzero even at n = 1.)

In Bohr’s model, the orbital angular momentum is quantized in units of ħ: L = nħ, where n is the principal quantum number for the orbit. For the ground state, n = 1, so the angular momentum has magnitude L = ħ. This means the electron carries one quantum of orbital angular momentum in the lowest orbit. (Spin would add its own ±ħ/2 contribution, but the orbital part in this model is nonzero even at n = 1.)

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