In Bohr’s model, the angular momentum of the electron in the nth orbit is L = nħ. What is L for n = 2 in terms of ħ?

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Multiple Choice

In Bohr’s model, the angular momentum of the electron in the nth orbit is L = nħ. What is L for n = 2 in terms of ħ?

Explanation:
In Bohr’s model, the electron’s orbital angular momentum is quantized in units of ħ, so L = nħ where n is a positive integer. For the second orbit, n = 2, giving L = 2ħ. (ħ = h/(2π), so this is twice Planck’s reduced constant.) This reflects the discrete, stepwise nature of angular momentum in early quantum theory—the angular momentum must be an integer multiple of ħ.

In Bohr’s model, the electron’s orbital angular momentum is quantized in units of ħ, so L = nħ where n is a positive integer. For the second orbit, n = 2, giving L = 2ħ. (ħ = h/(2π), so this is twice Planck’s reduced constant.) This reflects the discrete, stepwise nature of angular momentum in early quantum theory—the angular momentum must be an integer multiple of ħ.

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