If the radius of curvature is r and f = r/2, if r doubles, what does f become?

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Multiple Choice

If the radius of curvature is r and f = r/2, if r doubles, what does f become?

Explanation:
f scales with r because f = r/2. If r doubles to 2r, the new focal length becomes f' = (2r)/2 = r. That is twice the original value, since the original f was r/2. In other words, f becomes 2f. This reflects the direct proportionality between f and r: doubling r doubles f.

f scales with r because f = r/2. If r doubles to 2r, the new focal length becomes f' = (2r)/2 = r. That is twice the original value, since the original f was r/2. In other words, f becomes 2f. This reflects the direct proportionality between f and r: doubling r doubles f.

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