For a 1 kg object with c = 900 J/(kg·°C) heated by ΔT = 10°C, how much heat is added?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Study for the Praxis Physics Exam with interactive questions and detailed explanations to enhance your understanding of physics concepts. Prepare for your exam efficiently!

Multiple Choice

For a 1 kg object with c = 900 J/(kg·°C) heated by ΔT = 10°C, how much heat is added?

Explanation:
Heat added to a substance depends on its mass, how much energy per degree each kilogram needs (specific heat), and how much the temperature changes: Q = m c ΔT. With a 1 kg object, c = 900 J/(kg·°C), and a temperature rise ΔT = 10°C, the energy required is Q = 1 × 900 × 10 = 9000 J. So the heat added is 9000 joules (9 kJ). If you try different ΔT or masses, you’d get the other values (e.g., a smaller ΔT or a different mass would yield correspondingly different Q).

Heat added to a substance depends on its mass, how much energy per degree each kilogram needs (specific heat), and how much the temperature changes: Q = m c ΔT. With a 1 kg object, c = 900 J/(kg·°C), and a temperature rise ΔT = 10°C, the energy required is Q = 1 × 900 × 10 = 9000 J. So the heat added is 9000 joules (9 kJ). If you try different ΔT or masses, you’d get the other values (e.g., a smaller ΔT or a different mass would yield correspondingly different Q).

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy