A mass-spring system with mass 2 kg and spring constant 200 N/m has what approximate period?

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Multiple Choice

A mass-spring system with mass 2 kg and spring constant 200 N/m has what approximate period?

Explanation:
For a mass on a spring in simple harmonic motion, the period is T = 2π sqrt(m/k). With m = 2 kg and k = 200 N/m, m/k = 2/200 = 0.01, and sqrt(0.01) = 0.1. So T = 2π × 0.1 = 0.2π ≈ 0.628 s. The approximate period is about 0.63 seconds. This shows the period grows with mass and decreases with stiffer springs.

For a mass on a spring in simple harmonic motion, the period is T = 2π sqrt(m/k). With m = 2 kg and k = 200 N/m, m/k = 2/200 = 0.01, and sqrt(0.01) = 0.1. So T = 2π × 0.1 = 0.2π ≈ 0.628 s. The approximate period is about 0.63 seconds. This shows the period grows with mass and decreases with stiffer springs.

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