A car starts from rest and accelerates uniformly at 5 m/s^2 for 4 s. What is the car's final speed?

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Multiple Choice

A car starts from rest and accelerates uniformly at 5 m/s^2 for 4 s. What is the car's final speed?

Explanation:
Under constant acceleration, velocity changes by a t, so the final velocity is v = v0 + a t. Since the car starts from rest, v0 = 0. With an acceleration of 5 m/s^2 for 4 seconds, v = 0 + (5)(4) = 20 m/s. So the final speed is 20 m/s. This matches the idea that the velocity increases by 5 m/s each second, totaling 20 m/s after four seconds. The other values would require different times under the same acceleration.

Under constant acceleration, velocity changes by a t, so the final velocity is v = v0 + a t. Since the car starts from rest, v0 = 0. With an acceleration of 5 m/s^2 for 4 seconds, v = 0 + (5)(4) = 20 m/s. So the final speed is 20 m/s. This matches the idea that the velocity increases by 5 m/s each second, totaling 20 m/s after four seconds. The other values would require different times under the same acceleration.

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