A 5 kg block on a horizontal surface experiences kinetic friction with μk = 0.3. If the normal force is 49 N, what is the kinetic friction force?

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Multiple Choice

A 5 kg block on a horizontal surface experiences kinetic friction with μk = 0.3. If the normal force is 49 N, what is the kinetic friction force?

Explanation:
Kinetic friction scales with the normal force: F_k = μk N. On a horizontal surface with no vertical acceleration, the normal force equals the weight, which is mg = 5 × 9.8 ≈ 49 N. With μk = 0.3, the friction force is F_k = 0.3 × 49 N = 14.7 N, directed opposite the motion. The other numbers don’t come from multiplying μk by the given normal force, so they don’t match the actual friction magnitude.

Kinetic friction scales with the normal force: F_k = μk N. On a horizontal surface with no vertical acceleration, the normal force equals the weight, which is mg = 5 × 9.8 ≈ 49 N. With μk = 0.3, the friction force is F_k = 0.3 × 49 N = 14.7 N, directed opposite the motion. The other numbers don’t come from multiplying μk by the given normal force, so they don’t match the actual friction magnitude.

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