A 1 kg object with c = 900 J/(kg·°C) is heated by 5°C. How much heat is added?

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Multiple Choice

A 1 kg object with c = 900 J/(kg·°C) is heated by 5°C. How much heat is added?

Explanation:
Heat added is determined by Q = m × c × ΔT, where m is the mass, c is the specific heat, and ΔT is the temperature change. The specific heat c tells you how much energy is needed to raise 1 kg by 1°C. Here, m = 1 kg, c = 900 J/(kg·°C), and ΔT = 5°C. So Q = 1 × 900 × 5 = 4500 J. The units cancel to give joules, as expected. So the amount of heat added is 4500 J.

Heat added is determined by Q = m × c × ΔT, where m is the mass, c is the specific heat, and ΔT is the temperature change. The specific heat c tells you how much energy is needed to raise 1 kg by 1°C.

Here, m = 1 kg, c = 900 J/(kg·°C), and ΔT = 5°C. So Q = 1 × 900 × 5 = 4500 J. The units cancel to give joules, as expected.

So the amount of heat added is 4500 J.

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